Question

Выполните разложение на множители пожалуйста!!!а1) 2m3 – 18m; а2) z3 – 121z; а3) 28 – 7y2;б1) 7m2 + 14mn +7n2; б2 ) 20t2 + 20t +5; б3 ) –5m2 + 10mn –5n2;в1) 6n3 + 6m3; в2) z4 – 27zy3; в3) 2n4 – 16nm3

Answer 1

ответ:

20t2+20t+5=40t+5

Answer 2

а1) 2m^3 – 18m = 2m(m^2 – 9) = 2m(m – 3)(m + 3) а2) z^3 – 121z = z(z^2 – 121) = z(z – 11)(z + 11) а3) 28 – 7y^2 = 7(4 – y^2) = 7(2 + y)(2 – y) б1) 7m^2 + 14mn + 7n^2 = 7(m^2 + 2mn + n^2) = 7(m + n)^2 б2) 20t^2 + 20t + 5 = 5(4t^2 + 4t + 1) = 5(2t + 1)^2 б3) –5m^2 + 10mn – 5n^2 = –5(m^2 – 2mn + n^2) = –5(m – n)^2 в1) 6n^3 + 6m^3 = 6(n^3 + m^3) = 6(n + m)(n^2 – nm + m^2) в2) z^4 – 27zy^3 = z(z^3 – 27y^3) = z(z – 3y)(z^2 + 3yz + 9y^2) в3) 2n^4 – 16nm^3 = 2n(n^3 – 8m^3) = 2n(n – 2m)(n^2 + 2mn + 4m^2)