Question

(b^-3)^6 : b^17 = а) b^-35 б) b^-20 в) b^-1 г) b^-14

Answer 1

$(b^{-3})^6:b^{17}=b^{-3*6}:b^{17}=b^{-18}:b^{17}=b^{-18-17}=b^{-35};$

Answer 2

To simplify the expression $(b^{-3})^6 : b^{17}$, you can use the properties of exponents.

When you raise a power to another power, you multiply the exponents. In this case, you can multiply -3 (the exponent inside the parentheses) by 6:

$(b^{-3})^6 = b^{-3*6} = b^{-18}$

So, the expression becomes:

$\frac{b^{-18}}{b^{17}}$

Now, use the rule that when you divide two terms with the same base and different exponents, you subtract the exponents:

$b^{-18 - 17} = b^{-35}$

So, the simplified expression is $b^{-35}$.

The correct answer is а) $b^{-35}$.