Question

1)(2а-в²)·(2а+в²)= 2)(7в²-2а)²= 3)(3аm+2в²)²=

Answer 1

Вот памятка, как решать такие примеры

(a-b)(a+b)=a²-b²

(a+b)²=a²+2ab+b²

(a-b)²=a²-2ab+b²

1)(2а-в²)·(2а+в²) =  4a²-b⁴

2)(7в²-2а)² =  49b⁴-28ab²+4a²

3)(3аm+2в²)² = 9a²m²+12abm+4b⁴

Answer 2

Let's simplify each of the given expressions:

1. $(2a - b^2) \cdot (2a + b^2)$

Using the difference of squares formula $(a - b) \cdot (a + b) = a^2 - b^2$, we can simplify the expression:

$(2a - b^2) \cdot (2a + b^2) = (2a)^2 - (b^2)^2 = 4a^2 - b^4$

So, the simplified form is $4a^2 - b^4$.

2. $(7b^2 - 2a)^2$

This is already in the form of a square:

$(7b^2 - 2a)^2 = (7b^2 - 2a) \cdot (7b^2 - 2a)$

Using the difference of squares formula again:

$(7b^2 - 2a)^2 = (7b^2)^2 - (2a)^2 = 49b^4 - 4a^2$

So, the simplified form is $49b^4 - 4a^2$.

3. $(3am + 2b^2)^2$

This is also in the form of a square:

$(3am + 2b^2)^2 = (3am + 2b^2) \cdot (3am + 2b^2)$

Using the difference of squares formula:

$(3am + 2b^2)^2 = (3am)^2 - (2b^2)^2 = 9a^2m^2 - 4b^4$

So, the simplified form is $9a^2m^2 - 4b^4$.