Question

2cosп/6+tgп/4-2sinп/2

Answer 1

2cosπ/6+tgπ/4-2sinπ/2=2*√3/2+1-2*1=√3-1

Answer 2

I hope this helps you

Answer 3

It seems like you have an expression with trigonometric functions involving angles π/6, π/4, and π/2. Let's break down the expression step by step:

$2\cos(\frac{\pi}{6}) + \tan(\frac{\pi}{4}) - 2\sin(\frac{\pi}{2})$

First, let's evaluate the trigonometric functions for the given angles:

$\cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2}$ $\tan(\frac{\pi}{4}) = 1$ $\sin(\frac{\pi}{2}) = 1$

Now substitute these values back into the expression:

$2 \times \frac{\sqrt{3}}{2} + 1 - 2 \times 1$

Simplifying further:

$\sqrt{3} + 1 - 2$

Finally, combining like terms:

$\sqrt{3} - 1$

So, the simplified value of the expression $2\cos(\frac{\pi}{6}) + \tan(\frac{\pi}{4}) - 2\sin(\frac{\pi}{2})$ is $\sqrt{3} - 1$.