Question

2abc•(5abc-7ab)=? (k+d)•(k-dk-d)=?

Answer 1

1) 10а2b2c2-17а2b2c

2) k2-dk2-kd+dk-d2k-d2

Answer 2

Ответ:

$10a {}^{2} b {}^{2} c {}^{2} - 14a {}^{2}b {}^{2} c$

$k {}^{2} - dk {}^{2} - dk + dk - d {}^{2}k - d {}^{2} =$

$k {}^{2} - dk {}^{2} - d {}^{2} k - d {}^{2}$

Answer 3

Let's simplify the given expressions step by step:

1. 2abc•(5abc-7ab)

First, distribute the 2abc to both terms inside the parentheses:

= 2abc * 5abc - 2abc * 7ab

Now, multiply each term:

= 10a^2b^2c^2 - 14a^2bc^2

So, 2abc•(5abc-7ab) simplifies to 10a^2b^2c^2 - 14a^2bc^2.

2. (k+d)•(k-dk-d)

First, distribute (k+d) to both terms inside the parentheses:

= k(k-dk-d) + d(k-dk-d)

Now, simplify each term separately:

= k^2 - k^2d - kd + dk - dk^2 - d^2

Next, combine like terms:

= k^2 - k^2d - dk^2 - kd - dk - d^2

So, (k+d)•(k-dk-d) simplifies to k^2 - k^2d - dk^2 - kd - dk - d^2.