Question

3+(3^2)+(3^3)+(3^4)+(3^5)+(3^6)

Answer 1

3 + (3^2) + (3^3) + (3^4) + (3^5) + (3^6) = 3 + 9 + 27 + 81 + 243 + 729 = 1092.

Answer 2

To calculate the expression 3 + (3^2) + (3^3) + (3^4) + (3^5) + (3^6), you can simply raise 3 to the specified powers and then add the results together:

3^2 = 3 * 3 = 9 3^3 = 3 * 3 * 3 = 27 3^4 = 3 * 3 * 3 * 3 = 81 3^5 = 3 * 3 * 3 * 3 * 3 = 243 3^6 = 3 * 3 * 3 * 3 * 3 * 3 = 729

Now, add all these values together:

3 + 9 + 27 + 81 + 243 + 729 = 1092

So, 3 + (3^2) + (3^3) + (3^4) + (3^5) + (3^6) = 1092.