Question

1)33,6n-76 3/8 +78 1/9m-35n при m 24/25;n=102)29 4/13s+409 1/9t-30,5s_407,2t при s= -2,6;t=9/43​

Answer 1

Ответ:

33,6n-76 3/8+78 1/9m-35n =78 1/9m-1,4n-76 3/8

при n=10 m = 24/25

703/9×24/25-1,4×10-76 3/8=5624/75-14+76 3/8=

74 74/75-14-76 3/8=70 74/75-76 3/8=-2 151/600

29 4/13s+409 1/9t-30,5s-407,2t= 1 41/45t-1 5/26s

при s=-2, t=9/43

1 41/45×9/43-1 5/26×(-2)=86/45×9/43-31//26×(-2)=

2/5+31/13=2/5+2 5/13=26/65+5 25/65=5 51/65

Answer 2

To solve the given expressions for the specified values of $m$, $n$, $s$, and $t$, let's substitute the given values and perform the calculations step by step.

For the first expression: $33.6n - \frac{76}{8} + 78\frac{1}{9}m - 35n$

Given values: $m = \frac{24}{25}$ and $n = 102$

Substitute $n$ and $m$: $33.6(102) - \frac{76}{8} + 78\frac{1}{9}\left(\frac{24}{25}\right) - 35(102)$

Now, let's calculate this expression step by step: $= 3427.2 - 9.5 + \frac{1872}{25} - 3570$ $\approx 3427.2 - 9.5 + 74.88 - 3570$ $\approx -77.42$

For the second expression: $29\frac{4}{13}s + 409\frac{1}{9}t - 30.5s - 407.2t$

Given values: $s = -2.6$ and $t = \frac{9}{43}$

Substitute $s$ and $t$: $29\frac{4}{13}(-2.6) + 409\frac{1}{9}\left(\frac{9}{43}\right) - 30.5(-2.6) - 407.2\left(\frac{9}{43}\right)$

Now, let's calculate this expression step by step: $\approx -59.2 + 89.181 + 79.3 - 81.6$ $\approx 27.681$

So, with the given values of $m$, $n$, $s$, and $t$, the evaluated expressions are approximately:

1. $-77.42$
2. $27.681$