Question

√3-√2 √3+√2_____ - _______√3+√2 √3-√2

Answer 1

Ответ:

-4√6

Объяснение:

(√3-√2)(√3-√2) - (√3+√2)(√3+√2) / (√3+√2)(√3-√2) =

= (√3-√2)^2 - (√3+√2)^2 / (√3+√2)(√3-√2) =

= (3-2√6 +2-3-2√6-2) / 3-2 = -4√6

Answer 2

To simplify the given expression:

√3 - √2 √3 + √2

---

√3 + √2 √3 - √2

We can use the difference of squares formula, (a + b)(a - b) = a^2 - b^2, where in this case, a = √3 and b = √2.

So, we get:

(√3 - √2)(√3 + √2) (√3 + √2)(√3 - √2)

---

(√3 + √2)(√3 - √2) (√3 + √2)(√3 - √2)

Now, applying the difference of squares formula:

(√3)^2 - (√2)^2 (√3 + √2)(√3 - √2)

---

(√3 + √2)(√3 - √2) (√3 + √2)(√3 - √2)

Simplify further:

3 - 2 (√3 + √2)(√3 - √2)

---

1 (√3 + √2)(√3 - √2)

Now, subtract 2 from 3:

1 (√3 + √2)(√3 - √2)

• x ------------------- 1 (√3 + √2)(√3 - √2)

Since both the numerator and denominator are equal, they cancel out:

1

So, the simplified expression is 1.