Question

SOS 10x-x²=(x+5)•(x-4)​

Answer 1

Ответ:

Ответ нет потому что дискриминант менще нуля

Answer 2

To solve the equation $10x - x^2 = (x + 5)(x - 4)$, let's follow these steps:

1. Expand the right-hand side:

$(x + 5)(x - 4) = x^2 - 4x + 5x - 20 = x^2 + x - 20$

So now we have the equation:

$10x - x^2 = x^2 + x - 20$

2. Bring all terms to one side of the equation:

$10x - x^2 - x^2 - x + 20 = 0$

Simplifying further:

$10x - 2x^2 - x + 20 = 0$

3. Combine like terms:

$-2x^2 + 9x + 20 = 0$

4. To proceed, we can try to factor the quadratic equation or use the quadratic formula. Let's try factoring:

$-2x^2 + 9x + 20 = 0$

We can multiply the entire equation by -1 to make it easier:

$2x^2 - 9x - 20 = 0$

This can be factored as:

$(2x + 5)(x - 4) = 0$

Setting each factor equal to zero:

$2x + 5 = 0 \quad \text{or} \quad x - 4 = 0$

Solving these equations:

For $2x + 5 = 0$:

$2x = -5 \implies x = -\frac{5}{2}$

For $x - 4 = 0$:

$x = 4$

So, the solutions to the equation $10x - x^2 = (x + 5)(x - 4)$ are $x = -\frac{5}{2}$ and $x = 4$.