Question

A) (2x-5)" = 4x"; 6) (3x + 1)" - 3x(3x + 1); b) (7x-5)" = 7(x+1)".

Answer 1

А)(2х-5)-4х=0
-8х+20х=0
12х=0
х=-12

Answer 2

It looks like you have some expressions with variables x that involve exponentiation and simplification. Let's break down each of these expressions:

A) (2x-5)" = 4x": This expression appears to involve raising the quantity (2x-5) to some power and equating it to 4x. Without knowing the specific exponent (the number inside the quotation marks), we can't solve for x. To solve for x, you would need to know the value of the exponent.

6. (3x + 1)" - 3x(3x + 1): In this expression, you have (3x + 1) raised to some power (indicated by the quotation marks) and subtracted by 3x times (3x + 1). Similar to the previous expression, we can't simplify it further without knowing the specific value of the exponent inside the quotation marks.

B) (7x-5)" = 7(x+1)": This expression involves raising the quantity (7x-5) to some power and equating it to 7 times the quantity (x+1) raised to some power. Again, without knowing the specific exponent, we can't solve for x.

If you provide the specific values of the exponents or any additional information, I can help you solve these equations or simplify the expressions further.