Question

1) sin x = 1 2) cos x = 03) sin x = 1/24) tg x = -15) tg x = √36) 2tgx -3 = 07) 2sin x - √2 = 0​

Answer 1

Ответ:

решение смотри на фотографии

Answer 2

It seems like you've provided a list of trigonometric equations. I can help you find solutions for each of them:

1. $\sin(x) = 1$

   • There are no solutions for this equation since the sine function's range is $[-1, 1]$ and it never reaches 1.

2. $\cos(x) = 0$

   • This occurs when $x = \frac{\pi}{2} + n\pi$ where $n$ is an integer.

3. $\sin(x) = \frac{1}{2}$

   • This occurs when $x = \frac{\pi}{6} + 2n\pi$ or $x = \frac{5\pi}{6} + 2n\pi$ where $n$ is an integer.

4. $\tan(x) = -1$

   • This occurs when $x = \frac{3\pi}{4} + n\pi$ where $n$ is an integer.

5. $\tan(x) = \sqrt{3}$

   • This occurs when $x = \frac{\pi}{3} + n\pi$ where $n$ is an integer.

6. $2\tan(x) - 3 = 0$

   • $2\tan(x) = 3$ gives $\tan(x) = \frac{3}{2}$. This occurs when $x = \arctan\left(\frac{3}{2}\right) + n\pi$ where $n$ is an integer.

7. $2\sin(x) - \sqrt{2} = 0$

   • $2\sin(x) = \sqrt{2}$ gives $\sin(x) = \frac{\sqrt{2}}{2}$. This occurs when $x = \frac{\pi}{4} + 2n\pi$ where $n$ is an integer.

Keep in mind that $n$ is an integer and $\pi$ represents the mathematical constant pi. If you'd like any further explanations or have any other questions, feel free to ask!