Question

P1 (-1,2,-1);P2 (2,-1,-3) │P1P2│=?

Answer 1

Расстояние между точками, заданными своими координатами:
$|P_1P_2|= \sqrt{(2-(-1))^2+(-1-2)^2+(-3-(-1))^2} = \sqrt{9+9+4} =$ $\sqrt{22}.$

Answer 2

To find the distance between two points P1(-1, 2, -1) and P2(2, -1, -3), you can use the distance formula, which is based on the Euclidean distance in three-dimensional space:

Distance = √((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

where (x1, y1, z1) are the coordinates of point P1 and (x2, y2, z2) are the coordinates of point P2.

Given: P1(-1, 2, -1) P2(2, -1, -3)

Substitute the coordinates into the formula:

Distance = √((2 - (-1))^2 + (-1 - 2)^2 + (-3 - (-1))^2) Distance = √((3)^2 + (-3)^2 + (-2)^2) Distance = √(9 + 9 + 4) Distance = √22

So, the distance between points P1 and P2 is approximately √22 units.