Question

1) log0,9 x = −1 2) 0,9 степень х = −1

Answer 1

1)  log0,9 x = −1
     х=(0,9)⁻¹=(9/10)⁻¹=(10/9)= 1.1/9

2) 0,9ˣ  = −1  не имеет решений


    

Answer 2

It seems like you're working with equations involving logarithms and powers. The notation you're using, however, is a bit unclear. Let's clarify the equations:

1. $\log_{0.9} x = -1$
2. $0.9^x = -1$

I'll address both equations:

1. $\log_{0.9} x = -1$: In this equation, you're dealing with a logarithm base of 0.9. To solve for $x$, you need to rewrite the equation in exponential form:

$x = 0.9^{-1}$

Now, calculate $0.9^{-1}$:

$x = \frac{1}{0.9} \approx 1.111$

So, the solution to the equation is approximately $x = 1.111$.

2. $0.9^x = -1$: In this equation, you have an exponential equation involving the base $0.9$ and an unknown exponent $x$. However, it's important to note that $0.9$ raised to any real power will always be positive. Therefore, there is no real value of $x$ that will make $0.9^x$ equal to -1.

If you intended the equation to be something else, please provide the correct notation or clarify the equation further.