Question

A) (a+2)³ б) (2a-3)³

Answer 1

$a) (a+2)^3=a^3+3a^2*2+3a*2^2+2^3=a^3+6a^2+3a*4+8= \\ a^3+6a^2+12a+8 \\ \\ b) (2a-3)^3=(2a)^3-3*(2a)^2*3+3*2a*3^2-3^3= \\ = 8a^3-3*4a^2*3+3*2a*9-27=8a^3-36a^2+54a-27$

Answer 2

It looks like you have two expressions that involve cubing binomials. I can help you expand and simplify these expressions:

A) $(a + 2)^3$

To expand this expression, you can use the binomial expansion formula or the distributive property (FOIL):

$(a + 2)^3 = a^3 + 3a^2(2) + 3a(2^2) + 2^3$ $= a^3 + 6a^2 + 12a + 8$

B) $(2a - 3)^3$

Similarly, for this expression:

$(2a - 3)^3 = (2a)^3 + 3(2a)^2(-3) + 3(2a)(-3^2) + (-3)^3$ $= 8a^3 - 36a^2 + 54a - 27$

So, the expanded forms of the given expressions are:

A) $a^3 + 6a^2 + 12a + 8$ B) $8a^3 - 36a^2 + 54a - 27$