Question

12(х-3)-12(х+3)-18(х+3)(х-3)=0раскройте п. ж. скобки

Answer 1

12(х-3)-12(х+3)-18(х+3)(х-3)=0
12x-36-12x-36-18x в квадраті -9

Answer 2

To simplify the expression and expand the brackets, let's start step by step:

1. Distribute the 12 through the first set of parentheses (х-3): 12(х-3) = 12х - 36

2. Distribute the -12 through the second set of parentheses (х+3): -12(х+3) = -12х - 36

3. Expand the third set of parentheses (х+3)(х-3) using the FOIL method (First, Outer, Inner, Last): (х+3)(х-3) = х * х + х * (-3) + 3 * х + 3 * (-3) = х^2 - 3х + 3х - 9 = х^2 - 9

Now, let's rewrite the original expression with the simplified terms:

12х - 36 - 12х - 36 - 18(х^2 - 9) = 0

Now, let's simplify further:

Combine the like terms with 'х': (12х - 12х) = 0

Combine the constant terms (-36 - 36): (-36 - 36) = -72

Now, the expression becomes:

-72 - 18(х^2 - 9) = 0

Next, distribute the -18 through the parentheses: -18(х^2 - 9) = -18х^2 + 162

Now, the expression is:

-72 - 18х^2 + 162 = 0

To solve for 'х', let's move all the terms to one side of the equation:

-18х^2 + 90 = 0

Finally, divide both sides by -18 to solve for 'х':

х^2 - 5 = 0

Now, we can solve for 'х' by taking the square root of both sides:

х^2 = 5 х = ±√5

So, the solutions for 'х' are: х = √5 х = -√5