Question

В треугольнике АВС угол С равен 90 градусов, АС=13, АВ=20 найдите sinB

Answer 1

По теореме синусов
АВ/С=ВС/А=АС/В
20/90=13/sinB
sinB =90 * 13/20(все делённое на 20)
sin B= 58,5

Answer 2

To find sin(B) in the right-angled triangle ABC, where angle C is 90 degrees, and AC = 13 and AB = 20, you can use the trigonometric ratio for sine:

sin(B) = opposite / hypotenuse.

In this case, side AB is the side opposite angle B, and the hypotenuse is AC.

sin(B) = AB / AC.

sin(B) = 20 / 13 ≈ 1.538.

Keep in mind that the sine function gives a ratio and has no upper bound, so the value of sin(B) can exceed 1. It is common to express trigonometric values as decimals or fractions rather than percentages. Therefore, sin(B) ≈ 1.538.