Question

Функция задана формулой f(x)=5-x^2.найдите: f(1),f(2),f(-1),f(-3),f(0)

Answer 1

$f(x)=5-x^2\\\\f(1)=5-1=4\\\\f(2)=5-4=1\\\\f(-1)=5-(-1)^2=5-1=4\\\\f(-3)=5-(-3)^2=5-9=-4\\\\f(0)=5-0=5$

Answer 2

To find the values of the function $f(x)=5-x^2$ for the given inputs, simply substitute each value of $x$ into the formula and calculate the corresponding $f(x)$ value:

1. $f(1) = 5 - 1^2 = 5 - 1 = 4$
2. $f(2) = 5 - 2^2 = 5 - 4 = 1$
3. $f(-1) = 5 - (-1)^2 = 5 - 1 = 4$
4. $f(-3) = 5 - (-3)^2 = 5 - 9 = -4$
5. $f(0) = 5 - 0^2 = 5 - 0 = 5$

So, the values of the function $f(x)=5-x^2$ for the given inputs are:

$f(1) = 4$

$f(2) = 1$

$f(-1) = 4$

$f(-3) = -4$

$f(0) = 5$