Question

Раскрыть скобки: a) 15b-(4+2b)*6 б) 3a+(12-(7-4a)) в) 6(3y-4)-2(5y-6)

Answer 1

А)15b-(4+2b)=15b-4-2b=13b-4
б)3a+(12-7+4a)=3a+12-7+4a=7а+5
в)6(3y-4)-2(5y-6)=18y-24-10y+12=8y-12

Answer 2

Sure, let's expand the expressions by removing the parentheses:

a) 15b - (4 + 2b) * 6

Step 1: Distribute the -1 to the terms inside the parentheses: 15b - (4 * 6 + 2b * 6)

Step 2: Perform the multiplications inside the parentheses: 15b - (24 + 12b)

Step 3: Now, distribute the -1 to all the terms inside the second set of parentheses: 15b - 24 - 12b

Step 4: Combine like terms: (15b - 12b) - 24

Step 5: Simplify: 3b - 24

The expanded expression is: 3b - 24

b) 3a + (12 - (7 - 4a))

Step 1: Resolve the innermost set of parentheses: 3a + (12 - 7 + 4a)

Step 2: Simplify the terms inside the parentheses: 3a + (5 + 4a)

Step 3: Now, distribute the +1 to all the terms inside the second set of parentheses: 3a + 5 + 4a

Step 4: Combine like terms: (3a + 4a) + 5

Step 5: Simplify: 7a + 5

The expanded expression is: 7a + 5

c) 6(3y - 4) - 2(5y - 6)

Step 1: Distribute the 6 and the -2 to the terms inside the parentheses: (6 * 3y - 6 * 4) - (2 * 5y - 2 * 6)

Step 2: Perform the multiplications inside the parentheses: (18y - 24) - (10y - 12)

Step 3: Now, distribute the -1 to all the terms inside the second set of parentheses: 18y - 24 - 10y + 12

Step 4: Combine like terms: (18y - 10y) - (24 - 12)

Step 5: Simplify: 8y - 12

The expanded expression is: 8y - 12