Question

Найти область определения функции: log3(4x - 1b)

Answer 1

Решение
log₃ (4x - 16)
4x - 16 > 0
4x > 16
x > 4
D(y) = (4; + ∞)

Answer 2

To find the domain of the function $f(x) = \log_3(4x - b)$, we need to identify the values of $x$ for which the function is defined. The domain of a logarithmic function is determined by the argument inside the logarithm, which must be positive.

In this case, the argument of the logarithm is $4x - b$. For the function to be defined, $4x - b$ must be greater than 0:

$4x - b > 0$

To isolate $x$, we'll solve for it:

$4x > b$

$x > \frac{b}{4}$

So, the domain of the function $f(x) = \log_3(4x - b)$ is $x > \frac{b}{4}$.