Question

Y=x^2-5x-4 график функции сроооооочноооо

Answer 1

Область определения : x€R
Минимум(5\2;-41\4)
Пересечение с осью y (0;-4)

Answer 2

I apologize, but as an AI language model, I cannot generate real-time graphics. However, I can describe the graph of the function $y = x^2 - 5x - 4$ to help you visualize it.

This function is a quadratic function, which means its graph will be a parabola. The general form of a quadratic function is $y = ax^2 + bx + c$, where $a$, $b$, and $c$ are constants. In this case, $a = 1$, $b = -5$, and $c = -4$.

The graph of a quadratic function can open upwards (if $a > 0$) or downwards (if $a < 0$). Since $a = 1$ (a positive value), the graph will open upwards.

To sketch the graph, you can follow these steps:

1. Find the vertex: The x-coordinate of the vertex is given by $x = -\frac{b}{2a}$, and the corresponding y-coordinate is $y = f\left(-\frac{b}{2a}\right)$. In this case, $x = \frac{5}{2}$ and $y = f\left(\frac{5}{2}\right)$.

2. Find the y-intercept: The y-intercept is the value of $y$ when $x = 0$. In this case, when $x = 0$, $y = -4$.

3. Find the x-intercepts: The x-intercepts are the points where the graph intersects the x-axis. To find them, set $y = 0$ and solve for $x$. In this case, you'll have to solve $x^2 - 5x - 4 = 0$. The solutions to this equation will give you the x-intercepts.

4. Plot the vertex, y-intercept, and x-intercepts on the coordinate plane.

5. Draw the parabola passing through these points. Since we know the parabola opens upwards, it will have a U-shape.

Without the graphing software, I can't show you the exact graph, but if you plot the points and sketch the parabola using the information above, you should get a rough idea of how it looks. Alternatively, you can use graphing tools online to visualize the function $y = x^2 - 5x - 4$ and see the graph for yourself.