Question

F(x) =x^2 -3 найдите : f(1-корень из 3 ) + f (1+корень из 3)

Answer 1

Ответ на картинке внизу страницы

Answer 2

To find the value of $f(1-\sqrt{3}) + f(1+\sqrt{3})$, we need to substitute $x = 1-\sqrt{3}$ and $x = 1+\sqrt{3}$ into the function $f(x) = x^2 - 3$ and then perform the calculation.

1. Substitute $x = 1-\sqrt{3}$ into $f(x) = x^2 - 3$: $f(1-\sqrt{3}) = (1-\sqrt{3})^2 - 3$

2. Substitute $x = 1+\sqrt{3}$ into $f(x) = x^2 - 3$: $f(1+\sqrt{3}) = (1+\sqrt{3})^2 - 3$

Now, let's calculate these values:

$f(1-\sqrt{3}) = (1-\sqrt{3})^2 - 3 = (1-2\sqrt{3}+3) - 3 = -2\sqrt{3}$ $f(1+\sqrt{3}) = (1+\sqrt{3})^2 - 3 = (1+2\sqrt{3}+3) - 3 = 2\sqrt{3}$

Finally, add these two values together:

$f(1-\sqrt{3}) + f(1+\sqrt{3}) = -2\sqrt{3} + 2\sqrt{3} = 0$

So, $f(1-\sqrt{3}) + f(1+\sqrt{3}) = 0$.