Question

1)3; 9; 27; 2)4; 16; 64; 3)1; 2; 3; 4)1; 5; 25; Запишите последующие два члена числовой последовательности

Answer 1

1). 3,9,27,81, 243; 2). 4,16,64,256,1024; 3). 1,2,3,4,5. 4). 1,5,25,125,625.

Answer 2

1) 3; 9; 27; 81; 243

2) 4; 16; 64; 256; 1024

3) 1; 2; 3; 4; 5

4) 1; 5; 25; 125; 625

Answer 3

1. 81; 243 The pattern in the first sequence is that each term is obtained by multiplying the previous term by 3. So, to find the next two terms, we continue the pattern: 27 * 3 = 81 81 * 3 = 243

2. 256; 1024 In the second sequence, each term is obtained by squaring the previous term. To find the next two terms, we follow the pattern: 64 * 4 = 256 256 * 4 = 1024

3. 5; 6 The third sequence seems to be an arithmetic sequence with a common difference of 1. To find the next two terms, we add 1 to the last term: 4 + 1 = 5 5 + 1 = 6

4. 125; 625 The fourth sequence seems to be related to the squares of consecutive odd numbers. To find the next two terms, we square the next odd number: 3^2 = 9 5^2 = 25 7^2 = 49 9^2 = 81 11^2 = 121 13^2 = 169 15^2 = 225 17^2 = 289 19^2 = 361 21^2 = 441 23^2 = 529 25^2 = 625

So, the next two terms are: 25^2 = 625 27^2 = 729