Question

Решите уравнение. (b-2)^2-4b(2b-1)

Answer 1

(b-2)²-4b(2b-1)=b²-4b+4-8b²+4b=
4-7b²

Answer 2

To solve the equation, you must first set it equal to zero and then find the values of "b" that satisfy the equation. So, let's proceed step by step:

1. The equation is given as:

   (b - 2)^2 - 4b(2b - 1) = 0

2. Expand and simplify the equation:

   (b - 2)(b - 2) - 8b^2 + 4b = 0

3. Further simplify:

   (b - 2)^2 - 8b^2 + 4b = 0

4. Expand the squared term:

   (b^2 - 4b + 4) - 8b^2 + 4b = 0

5. Combine like terms:

   -7b^2 + 4 = 0

6. Move the constant term to the other side:

   -7b^2 = -4

7. Divide both sides by -7 to isolate b^2:

   b^2 = 4/7

8. Take the square root of both sides:

   b = ±√(4/7)

Therefore, the solutions for "b" are:

b = √(4/7) ≈ ±0.7559