Question

8*(x-3)-4*(5-x)=?x*(x²+x²-4)-x³-(x-2)=?(-3x²y⁴)²*0,2y²=?

Answer 1

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Answer 2

Let's solve each of the expressions step by step:

1. 8*(x-3) - 4*(5-x)

First, distribute the numbers inside the parentheses:

8x - 24 - 4(5) + 4x

Simplify the terms:

8x - 24 - 20 + 4x

Combine like terms:

12x - 44

So, the simplified form of 8*(x-3) - 4*(5-x) is 12x - 44.

2. x*(x²+x²-4) - x³ - (x-2)

Combine the terms inside the parentheses:

x*(2x² - 4) - x³ - x + 2

Distribute x:

2x³ - 4x - x³ - x + 2

Combine like terms:

x³ - 5x + 2

So, the simplified form of x*(x²+x²-4) - x³ - (x-2) is x³ - 5x + 2.

3. (-3x²y⁴)² * 0.2y²

First, calculate the square of (-3x²y⁴):

(-3x²y⁴)² = 9x⁴y⁸

Now multiply this result by 0.2y²:

9x⁴y⁸ * 0.2y²

Multiply the coefficients (numbers) and combine the variables (x and y):

1.8x⁴y¹⁰

So, the simplified form of (-3x²y⁴)² * 0.2y² is 1.8x⁴y¹⁰.