Question

Sin(-П/3)- cos(-П/6)=

Answer 1

на фото..................

Answer 2

Let's evaluate the expression step by step:

1. Sin(-π/3): The sine function is an odd function, which means sin(-x) = -sin(x). So, sin(-π/3) = -sin(π/3).

2. Cos(-π/6): The cosine function is an even function, which means cos(-x) = cos(x). So, cos(-π/6) = cos(π/6).

Now, let's find the values of sin(π/3) and cos(π/6):

sin(π/3) = √3/2 (approximately 0.866) cos(π/6) = √3/2 (approximately 0.866)

Now, plug the values back into the original expression:

Sin(-π/3) - Cos(-π/6) = -sin(π/3) - cos(π/6) = -√3/2 - √3/2 = -2 * √3/2 = -√3

So, Sin(-π/3) - Cos(-π/6) equals -√3 (approximately -1.732).