Question

(tgx-1)(2sin^2+3)=0 решить уровнение

Answer 1

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Answer 2

To solve the equation (tgx-1)(2sin^2x+3) = 0, we need to find the values of x that make the expression equal to zero. To do this, we set each factor inside the parentheses equal to zero and solve for x:

1. tgx - 1 = 0: Add 1 to both sides: tgx = 1

2. 2sin^2x + 3 = 0: Subtract 3 from both sides: 2sin^2x = -3

   Now, divide both sides by 2: sin^2x = -3/2

However, there is an issue with the equation. The sine function squared (sin^2x) cannot be negative. It ranges from 0 to 1, but it can never be negative. Therefore, there are no real solutions for this equation.

So, the original equation (tgx-1)(2sin^2x+3) = 0 has no real solutions for x.