Question

(2a+1)^2+2(2a+1)(a-1)+(a-1)^2 при a= -3,5 (с решением)

Answer 1

$(2 \times ( - 3.5) + 1 {)}^{2} + 2(2 \times ( - 3.5) + 1) \times ( - 3.5 - 1) + ( - 3.5 - 1 {)}^{2} = \\ = ( - 7 + 1 {)}^{2} + 2( - 7 + 1) \times ( - 4.5) - ( - 4.5 {)}^{2} = \\ = ( - 6 {)}^{2} + 2 \times ( - 6) \times ( - 4.5) + ( - \frac{9}{2} {)}^{2} = \\ = 36 + 54 + \frac{81}{4} = \\ = 90 + \frac{81}{4} = \frac{441}{4} = 110 \frac{1}{4}$

Answer 2

To find the value of the expression (2a+1)^2 + 2(2a+1)(a-1) + (a-1)^2 when a = -3.5, we simply need to substitute the value of a into the expression and perform the arithmetic operations.

Step 1: Replace 'a' with '-3.5' in the expression: (2(-3.5) + 1)^2 + 2(2(-3.5) + 1)(-3.5 - 1) + (-3.5 - 1)^2

Step 2: Simplify each term: (-7 + 1)^2 + 2(-7 + 1)(-4.5) + (-4.5)^2 (-6)^2 + 2(-6)(-4.5) + 20.25 36 + 54 + 20.25 110.25

So, when a = -3.5, the value of the expression (2a+1)^2 + 2(2a+1)(a-1) + (a-1)^2 is 110.25.