Question

Даны векторы a (5;-1;2) b (3;2;-3) найти a-2b​

Answer 1

a (5;-1;2) b (3;2;-3)

2b (2*3;2*2;2* -3) = (6;4;-6)

a-2b (5-6;-1-4;2+6) = (-1;-5;8)

Answer 2

To find the vector subtraction a - 2b, you need to subtract 2 times the vector b from vector a. Let's perform the calculations:

a = (5, -1, 2) b = (3, 2, -3)

a - 2b = (5, -1, 2) - 2 * (3, 2, -3)

To perform the subtraction, you subtract corresponding components of the two vectors:

a - 2b = (5 - 2 * 3, -1 - 2 * 2, 2 - 2 * (-3))

a - 2b = (5 - 6, -1 - 4, 2 + 6)

a - 2b = (-1, -5, 8)

So, the result of the vector subtraction a - 2b is (-1, -5, 8).