Question

Даю 34 балла за решение!!! a)1) (4+а)²= 2) (2х-1) (2х+1)= 3) (2а+3b)²= 4) (х-3)²= 4) (х-3)²= b)1) (5+х)²= 2) (1-3х)²= 3) (3а-10b)²= 4) (х+4)(х-4)= 5) (2х-5)²= B)1) (а-6)²= 2) (5х+2у)²= 3) (10+7к)²= 4) (3с-1)(3с+1)= 5) (9+х)²= g)1) (с-х)²= 2) (5х+у)²= 3) (а-4)²= 4) (а-2с)(а+2с)= 5) (5х-3у)²= D)1) (1+а)²= 2) (8х-1)(8х+1)= 3) (3а-11b)²= 4) (х+8)²= 5) (с+у)²=

Answer 1

16+8х+х^2
4х^2-1
4х^2+12ху+9у^2
Х^2-6х+9

25+10х+х^2
1-6х+9х^2
9х^2-60ху+100у^2
Х^2-16
4х^2-20х+25

Х^2-12х+36
25х2+20ху+4у^2
100+140х+49х^2
9х^2-1
81+18х+х^2

Х^2-2ху+у^2
25х^2+10ху+у^2
Х^2-8х+16
Х^2-4у^2
25х^2-30ху+9у^2

1+2х+х^2
64х^2-1
9х^2-66ху+121у^2
Х^2+16х+64
Х^2+2ху+у^2

Answer 2

To solve these expressions, I will expand each one as follows:

a)1) $(4+a)^2$ = $4^2 + 2 \cdot 4 \cdot a + a^2 = 16 + 8a + a^2$

a)2) $(2x-1)(2x+1)$ = $2x \cdot 2x + 2x \cdot 1 - 1 \cdot 2x - 1 \cdot 1 = 4x^2 + 2x - 2x - 1 = 4x^2 - 1$

a)3) $(2a+3b)^2$ = $2a \cdot 2a + 2 \cdot 2a \cdot 3b + 3b \cdot 3b = 4a^2 + 12ab + 9b^2$

a)4) $(x-3)^2$ = $x^2 - 3 \cdot x - 3 \cdot x + 3^2 = x^2 - 6x + 9$

b)1) $(5+x)^2$ = $5^2 + 2 \cdot 5 \cdot x + x^2 = 25 + 10x + x^2$

b)2) $(1-3x)^2$ = $1^2 - 2 \cdot 1 \cdot 3x + (3x)^2 = 1 - 6x + 9x^2$

b)3) $(3a-10b)^2$ = $3a \cdot 3a - 2 \cdot 3a \cdot 10b + 10b \cdot 10b = 9a^2 - 60ab + 100b^2$

b)4) $(x+4)(x-4)$ = $x \cdot x - 4 \cdot x + 4 \cdot x - 4 \cdot 4 = x^2 - 16$

b)5) $(2x-5)^2$ = $2x \cdot 2x - 2 \cdot 2x \cdot 5 + 5^2 = 4x^2 - 20x + 25$

B)1) $(a-6)^2$ = $a^2 - 6 \cdot a - 6 \cdot a + 6^2 = a^2 - 12a + 36$

B)2) $(5x+2y)^2$ = $5x \cdot 5x + 2 \cdot 5x \cdot 2y + 2y \cdot 2y = 25x^2 + 20xy + 4y^2$

B)3) $(10+7k)^2$ = $10^2 + 2 \cdot 10 \cdot 7k + 7k^2 = 100 + 140k + 49k^2$

B)4) $(3c-1)$