Question

При каких значениях аргумента x значение функции f(x)=-1/4x^2 равно -4​

Answer 1

$-\frac{1}{4}x^2=-4\ /\cdot(-4)\\\\x^2=16\\\\x^2-16=0\\\\(x-4)(x+4)=0\\\\x-4=0 \ \ \ \ \ x+4=0\\\\x=4\ \ \ \ \ \ \ \ \ \ x=-4$

Ответ: -4; 4

Answer 2

To find the values of the argument "x" for which the function $f(x) = -\frac{1}{4}x^2$ is equal to -4, we can set up the equation:

$f(x) = -\frac{1}{4}x^2 = -4.$

Now, let's solve for "x":

$-\frac{1}{4}x^2 = -4.$

To get rid of the coefficient "-1/4", we can multiply both sides of the equation by -4:

$-4 \times \left(-\frac{1}{4}x^2\right) = -4 \times (-4).$

$x^2 = 16.$

Next, we isolate "x" by taking the square root of both sides. Remember that there are two possible solutions for the square root:

$x = \pm \sqrt{16}.$

Finally, we simplify the square root:

$x = \pm 4.$

Therefore, when the argument "x" takes the values $x = 4$ or $x = -4$, the value of the function $f(x) = -\frac{1}{4}x^2$ will be equal to -4.