Question

47а2b4 — 8аb3 + 3а2b­ — 45а2b4 + 6аb3 при а = 2, b =-3.

Answer 1

$47 {a}^{2} {b}^{4} - 8 {ab}^{3} + 3 {a}^{2} b - 45 {a}^{2} {b}^{4} \\ + 6 {ab}^{3} = 2 {a}^{2} {b}^{4} - 2 {ab}^{3} + 3 {a}^{2} b = \\ 2 \times 4 \times 81 - 4 \times ( - 27) - 36 =$

$648 +10 8 - 36 = 723$

Вроде так

Answer 2

To evaluate the given expression for the given values of a and b, simply substitute a = 2 and b = -3 into the expression and perform the arithmetic.

Given expression: 47а^2b4 - 8аb^3 + 3а^2b ­- 45а^2b4 + 6аb^3

Now, replace a with 2 and b with -3:

= 47 * (2^2) * (-3)^4 - 8 * (2) * (-3)^3 + 3 * (2^2) * (-3) - 45 * (2^2) * (-3)^4 + 6 * (2) * (-3)^3

Calculate the values:

= 47 * 4 * 81 - 8 * 2 * -27 + 3 * 4 * -3 - 45 * 4 * 81 + 6 * 2 * -27

= 152 * 81 + 432 + -36 - 14580 - 324

= 12312 + 108 - 14580 - 324

= -2112

Therefore, the value of the expression with a = 2 and b = -3 is -2112.