Question

6x-3x^2 дробь x^2-4 чему равен

Answer 1

если что-то не понятно спрашивайте)

Answer 2

To find the value of the expression $\frac{6x-3x^2}{x^2-4}$, we first need to factor both the numerator and the denominator:

Numerator: $6x - 3x^2 = 3x(2 - x)$

Denominator: $x^2 - 4 = (x+2)(x-2)$

Now, we can simplify the expression by canceling out common factors between the numerator and the denominator:

$\frac{6x-3x^2}{x^2-4} = \frac{3x(2 - x)}{(x+2)(x-2)}$

We can see that there's a common factor of $3x$ in the numerator and denominator, which we can cancel out:

$\frac{6x-3x^2}{x^2-4} = \frac{3x(2 - x)}{(x+2)(x-2)} = \frac{2-x}{x+2}$

So, the simplified value of the expression is $\frac{2-x}{x+2}$.