Question

15x^2+4=16x 7x^2=4x-3 2x-5x^2=0 5x^2-20=0 7x+3+4x^2=0 x^2-9x+18=0 Dискриминант

Answer 1

Ответ:1) 9x 2) 4y 3) 0 4) 0 5) 39x

Объяснение:

Answer 2

To find the discriminant (Δ) of a quadratic equation of the form ax^2 + bx + c = 0, you use the formula Δ = b^2 - 4ac. Let's calculate the discriminant for the given quadratic equations:

1. 15x^2 + 4 = 16x Rewrite the equation as 15x^2 - 16x + 4 = 0 a = 15, b = -16, c = 4 Δ = (-16)^2 - 4 * 15 * 4 Δ = 256 - 240 Δ = 16

2. 7x^2 = 4x - 3 Rewrite the equation as 7x^2 - 4x + 3 = 0 a = 7, b = -4, c = 3 Δ = (-4)^2 - 4 * 7 * 3 Δ = 16 - 84 Δ = -68

3. 2x - 5x^2 = 0 Rewrite the equation as -5x^2 + 2x = 0 a = -5, b = 2, c = 0 Δ = 2^2 - 4 * (-5) * 0 Δ = 4

4. 5x^2 - 20 = 0 a = 5, b = 0, c = -20 Δ = 0^2 - 4 * 5 * (-20) Δ = 0 + 400 Δ = 400

5. 7x + 3 + 4x^2 = 0 Rewrite the equation as 4x^2 + 7x + 3 = 0 a = 4, b = 7, c = 3 Δ = 7^2 - 4 * 4 * 3 Δ = 49 - 48 Δ = 1

6. x^2 - 9x + 18 = 0 a = 1, b = -9, c = 18 Δ = (-9)^2 - 4 * 1 * 18 Δ = 81 - 72 Δ = 9

In summary, the discriminant for each equation is as follows:

1. Δ = 16
2. Δ = -68
3. Δ = 4
4. Δ = 400
5. Δ = 1
6. Δ = 9