Question

Решите систему уравнений{5x-y=16{8x+3y=21​ Смотреть ответ sashulya1403 sashulya1403 Ответ: (3; -1) Объяснение: Решим методом сложения: {5x - y = 16 | * 3 ( умножаем первое уравнение на 3) {8x + 3y = 21 {15x - 3y = 48 {8x + 3y = 21 -3y и +3y взаимно уничтожаются, остаётся: {15x = 48 {8x = 21 15x + 8x = 48 + 21 23x = 69 | :23 ( делим обе части на 23 ) x = 3 Подставляем полученный х в любое из уравнений: 5x - y = 16 5 * 3 - y = 16 15 - y = 16 y = 15 - 16 y = -1 Ответ: (3;-1) Проверка: Подставляем полученный x и y в первое уравнение: 5 * 3 - 1 * (-1) = 16 15 + 1 = 16 16 = 16 Равенство выполнено, а значит ответы правильные. Новые вопросы в Алгебра (x+2)²+(x-3y)²=0 срочно даю дофига ​ Помогите пожалуйста X^2-10x+16>=0 6. Відомо, що а+b=5, ab=-2. Знайдіть значення виразу (a-b)в квадраті​ Знайти f(27), якщо f(x) = √3х​a) 9 b)-9 в) 4 г)6 Знайдіть знаменник геометричної прогресії... 75; 15; 3;.....​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . 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Answer 1

Вы рассмотрели систему уравнений и правильно решили её. Ответ (3; -1) верен.

Теперь давайте рассмотрим ваш следующий вопрос:

1. Уравнение (x+2)² + (x-3y)² = 0: Это уравнение представляет собой сумму двух квадратов, и в данном случае оно равно нулю. Квадраты любых реальных чисел всегда неотрицательны, поэтому сумма двух квадратов также не может быть равной нулю, за исключением случая, когда оба квадрата равны нулю. То есть, для того чтобы данное уравнение выполнилось, необходимо, чтобы (x+2)² = 0 и (x-3y)² = 0, но это возможно только в случае, когда x = -2 и x = 3y соответственно. Таким образом, получается система уравнений: x = -2 и x = 3y.

2. Неравенство X^2 - 10x + 16 ≥ 0: Для решения данного неравенства, давайте начнем с нахождения корней квадратного трёхчлена X^2 - 10x + 16 = 0. Решая это уравнение, получим два корня: x = 5 + 3i и x = 5 - 3i, где i - это мнимая единица. Так как коэффициент при x^2 положителен, это означает, что уравнение имеет комплексные корни, и кривая параболы не пересекает ось x.

   Теперь, неравенство X^2 - 10x + 16 ≥ 0 означает, что наша парабола либо полностью находится выше оси x (не пересекая её), либо касается её в одной точке. Так как у нас нет реальных корней, это неравенство будет выполнено для всех реальных значений x. Итак, решением неравенства является множество всех реальных чисел: (-∞, +∞).

Что касается вашего вопроса о "6. Відомо, що а+b=", у вас осталось недописанное предложение. Пожалуйста, дополните вопрос, и я буду рад помочь вам.