Вопрос задан 06.06.2023 в 16:28. Предмет Алгебра. Спрашивает Бондар Лера.

ДАЮ 100 БАЛОВ СРОЧНО!!!!!!!!!! 1(3б). Розв’яжіть систему рівнянь графічно {3x-y=5 {x+4y=6 2(3б).

Розв’яжіть систему рівнянь способом додавання: {x+4y=6 {3x-y=8 Смотреть ответ rilexers rilexers Ответ: 1. Графічний метод: Ми можемо зобразити кожне рівняння на координатній площині та знайти їх перетин, де відповідні значення x та y будуть розв’язками системи. Рівняння першої прямої: 3x-y=5 Або y=3x-5 (перенесемо y в ліву частину, а решту в праву) Рівняння другої прямої: x+4y=6 Або y= (-1/4)x+3/2 Тепер ми можемо побудувати графіки обох рівнянь та знайти їх перетин, що й буде розв'язком системи: Отже, розв’язком системи є значення: (x, y) ≈ (1, 1). 2. Метод додавання: Метод полягає в тому, щоб додати ліві та праві частини рівнянь з метою ізольованого знаходження змінних. Спочатку ми помножимо перше рівняння на 4, щоб у нього зникла y: {4x + 16y=24 (множимо перше рівняння на 4) {3x - y = 8 Тепер ми можемо додати дві рівності відразу (або можемо віднімати). {4x + 16y =24 {+ 3x - y = 8 ----------------- 7x + 15y = 32 Тепер із другого рівняння ми можемо знайти вираз для однієї зі змінних, наприклад, y: y = 2x -3 Замінимо відповідний вираз нашої новій системи: 7x + 15(2x -3) = 32 Тепер ми можемо вирішити це рівняння для x: 7x + 30x -45 = 32 37x = 77 x ≈ 2,08 Тепер ми можемо знайти y, підставивши x в одне з початкових рівнянь, наприклад, друге: x + 4y = 6 2,08 + 4y = 6 4y = 3,92 y ≈ 0,98 Отже, розв’язок системи рівнянь методом додавання: (x, y) ≈ (2,08, 0,98). Великолепно объяснил Новые вопросы в Алгебра Розв'язати рівняння залежно від значення параметра а допоможіть будь ласка допоможіть даю 30 балів благаю терміново ​ Срочно!!! Помогите решить задачу!!! 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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Підставимо x, яке ми знайшли, у друге початкове рівняння:

2,08 + 4y = 6

4y = 6 - 2,08

4y ≈ 3,92

y ≈ 0,98

Таким чином, розв'язком системи є (x, y) ≈ (2,08, 0,98).

Нагадую, що ці значення є приблизними, оскільки вони отримані округленням чисел під час розрахунків.

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