Вопрос задан 15.06.2023 в 02:21. Предмет Алгебра. Спрашивает Свириденко Даниил.

1. Решите систему уравнений графическим способом: {2х-у=3, х+у=3. 2. Решите систему уравнений

любым из двух точных способов: {6х-2у=7-9у, 8х+3у=52х +1. Смотреть ответ ludmilaksenija2005 ludmilaksenija2005 Объяснение: 1 {2Х-у=3 {Х+у=3 2х-у=3 - красная -у=3-2х У=2х-3 Х 0 1 У - 3 - 2 Х+у=3 синяя У=3-х Х 0 1 У 3 2 Решение точка пересечения (2 ; 1) 2 {6х-2у=7-9у {8х+3у=52х+1 {6х-2у+9у=7 {8х+3у-52х=1 {6х+7у=7 |×3 {-44х+3у=1 |×(-7) {18х+21у= 21 {308х-21у= - 7 + ————— 326х=14 Х=14/326=7/163 7у=7-6х 7у=7-6×7/163 7у=7-42/163 7у=6 121/163 У=6 121/163×1/7=1099/163×1/7=157/163 Ответ : (7/163; 157/163) Новые вопросы в Алгебра 6. (2 б) Радіус кола, описаного навколо прямокутного трикутника. дорівнюе 10 см. Точка дотику вписаного кола ділить гіпотенузу на вiдрiзки, один із як … их 8 см. Знайдіть катети прямокутного трикутника, якщо радіус вписаного кола 4 см. Побудуйте в одній системі координат графіки функцій у = 3x - 7 i y = 2 та знайдіть координати точки їх перетину. ПОМОГИТЕ СРОЧНОООО На картинке фигуры трачу 100 даю вам 50 срочноРешите пожалуйста немецкая математика 7 классПереведите сами тут неразбириха от переводчикаКвадраты нари … сованы не в масштабе. Условия приводят к размерам в см.а) Назовите длину периметра U и площадь А для каждого из трех четырехугольников.б) Вычислить периметр четырехугольника 1 для x = 4 и y = 6. c) Вычислить площадь четырехугольника 2 и четырехугольника 3 для x = 1,5и у = -2. Укажите (округлив до процента), какой процент площади четырехугольника 3 составляет площадь четырехугольника 2 при данных значениях х и у​ помогите пожалуйста, даю 30 баллов дана функция y=x²+6х+6 1.название функции-....., графиком которой является-..... 2.график пересекает ось Оу в точке (...;...) 3.координаты вершины гра … фика (...;...) 4.Область значений данной функции E(f)=[...;+∞) ПОМОГИТЕ ПРОШУ ДАЮ 25 БАЛЛОВ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . 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Решение системы уравнений графическим способом:

Для решения системы уравнений графическим способом, нужно построить графики каждого уравнения и найти точку их пересечения.

1. Уравнение 1: 2х - у = 3 Уравнение 2: х + у = 3

Для уравнения 1: Подставим некоторые значения для удобства. Пусть x = 0, тогда 2 * 0 - y = 3, откуда y = -3. Пусть y = 0, тогда 2x - 0 = 3, откуда x = 3/2 = 1.5.

Таким образом, у нас есть две точки на графике уравнения 1: (0, -3) и (1.5, 0).

Для уравнения 2: Подставим некоторые значения. Пусть x = 0, тогда 0 + y = 3, откуда y = 3. Пусть y = 0, тогда x + 0 = 3, откуда x = 3.

Таким образом, у нас есть две точки на графике уравнения 2: (0, 3) и (3, 0).

Теперь построим графики обоих уравнений и найдем точку их пересечения:

``` | 3 | . (0, 3) | /| | / | | / | | / | | / | | / | |/ | o-------+-------+ (0, -3) (3, 0) x ```

Точка пересечения графиков находится в точке (1.5, 1.5). Следовательно, решение системы уравнений графическим способом равно x = 1.5, y = 1.5.

Решение системы уравнений другими методами:

2. Уравнение 1: 6х - 2у = 7 - 9у Уравнение 2: 8х + 3у = 52х + 1

Мы можем решить эту систему уравнений, используя любой из двух точных методов, например, метод подстановки или метод исключения.

Метод подстановки: Используем первое уравнение для выражения x через y: 6х - 2у = 7 - 9у 6х = 7 - 9у + 2у 6х = 7 - 7у x = (7 - 7у)/6

Теперь подставим это выражение для x во второе уравнение: 8х + 3у = 52х + 1 8((7 - 7у)/6) + 3у = 52((7 - 7у)/6) + 1 (56 - 56у)/6 + 3у = (364 - 364у)/6 + 1 56 - 56у + 18у = 364 - 364у + 6 -38у + 56у = 364 - 56 18у = 308 у = 308/18 у = 17.11

Теперь, используя это значение у, найдем значение x, подставив его в первое уравнение: 6х - 2(17.11) = 7 - 9(17.11) 6х - 34.22 = 7 - 153.99 6х = 7 - 153.99 + 34.22 6х = -112.77 х = -112.77/6 х = -18.8

Таким образом, решение системы уравнений методом подстановки равно x = -18.8, y = 17.11.

Метод исключения: Умножим первое уравнение на 4 и второе уравнение на 3, чтобы избавиться от коэффициента у при х: 24х - 8у = 28 - 36у 24х + 9у = 156х + 3

Теперь вычтем первое уравнение из второго: 24х + 9у - (24х - 8у) = 156х + 3 - (28 - 36у) 9у + 8у = 156х + 3 - 28 + 36у 17у = 156х - 25 + 36у -19у = 156х - 25 у = (156х - 25)/(-19)

Теперь подставим это выражение для у в первое уравнение: 6х - 2((156х - 25)/(-19)) = 7 - 9((156х - 25)/(-19)) 6х + (312х - 50)/19 = 7 + (1404х - 225)/19 19(6х) + 312х - 50 = 19(7) + 1404х - 225 114х + 312х - 1404х = 133 - 225 + 50 -978х = -42 х = -42/(-978) х = 7/163

Таким образом, решение системы уравнений методом исключения равно x = 7/163, y = (156х - 25)/(-19).

Ответ:

1. Графическим способом: x = 1.5, y = 1.5. 2. Метод подстановки: x = -18.8, y = 17.11. 3. Метод исключения: x = 7/163, y = (156х - 25)/(-19).

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