Question

X^2+4x√3+6 При x = √3 + 1

Answer 1

Ответ:

x^2+4x√3+6=$\sqrt{3}^{2} +2\sqrt{3}+1 +4*3+4\sqrt{3}+6 =3+2\sqrt{3} +1+12+4\sqrt{3} +6=22+6\sqrt{3}$

Объяснение:

Answer 2

To evaluate the expression x^2 + 4x√3 + 6 when x = √3 + 1, we can substitute the value of x into the expression and simplify it.

Let's substitute x = √3 + 1 into the expression:

(√3 + 1)^2 + 4(√3 + 1)√3 + 6

Expanding (√3 + 1)^2: = (√3 + 1)(√3 + 1) + 4(√3 + 1)√3 + 6 = 3 + 2√3 + 1 + 4√3 + 4 + 6

Simplifying: = 3 + 1 + 4 + 2√3 + 4√3 + 6 = 14 + 6√3

Therefore, when x = √3 + 1, the expression x^2 + 4x√3 + 6 simplifies to 14 + 6√3.