Question

1)y(y-1)-(y-5)²=2 2) 16y(2-y)+(4y-5)²=0​

Answer 1

Ответ:

y=-3

Объяснение:

y2-y+y2-5y=2

6y=2

y=2:6

y=-3

Answer 2

Let's solve the given equations step by step:

1. y(y - 1) - (y - 5)² = 2

Expanding the equation, we have:

y² - y - (y² - 10y + 25) = 2

Simplifying further:

y² - y - y² + 10y - 25 = 2

Combining like terms:

-11y + 25 - 2 = 0

-11y + 23 = 0

To isolate y, we can subtract 23 from both sides:

-11y = -23

Now, dividing both sides by -11:

y = (-23) / (-11)

Simplifying the right side:

y = 23/11

Therefore, the solution to the equation is y = 23/11.

2. 16y(2 - y) + (4y - 5)² = 0

Expanding the equation, we have:

32y - 16y² + 16y² - 40y + 25 = 0

Combining like terms:

32y - 40y + 25 = 0

-8y + 25 = 0

To isolate y, we can subtract 25 from both sides:

-8y = -25

Now, dividing both sides by -8:

y = (-25) / (-8)

Simplifying the right side:

y = 25/8

Therefore, the solution to the equation is y = 25/8.

In summary:

1. y = 23/11
2. y = 25/8