Question

(с-4)² -2(а+8с)² Х²+10ху+25у² (х+7у)²-х(х+с)

Answer 1

Объяснение:

1. (с-4)`=с'-4'
2. =-2а'-16с'
3. =26у'+10ху
4. =х'+7у'-х'-сх=7у'-сх

'-это кв

Answer 2

Let's simplify the given expression step by step:

1. Start with the expression: (с-4)² - 2(a+8с)²

   Expand the square of (с-4): (с-4)² = (с-4)(с-4) = с² - 8с + 16

   Expand the square of (a+8с): (a+8с)² = (a+8с)(a+8с) = a² + 16ac + 64с²

   Substitute the expanded forms back into the expression: (с-4)² - 2(a+8с)² = (с² - 8с + 16) - 2(a² + 16ac + 64с²) = с² - 8с + 16 - 2a² - 32ac - 128с²

2. Move on to the expression: х² + 10ху + 25у²

   This expression cannot be further simplified since it is already in its simplest form.

3. Proceed with the expression: (х+7у)² - х(х+с)

   Expand the square of (х+7у): (х+7у)² = (х+7у)(х+7у) = х² + 14ху + 49у²

   Distribute the х term in the second part: х(х+с) = х² + хс

   Substitute the expanded forms back into the expression: (х+7у)² - х(х+с) = (х² + 14ху + 49у²) - (х² + хс) = х² + 14ху + 49у² - х² - хс = 14ху + 49у² - хс

So, the simplified expression is: с² - 8с + 16 - 2a² - 32ac - 128с² + х² + 10ху + 25у² + 14ху + 49у² - хс

Simplifying further: -2a² - 32ac - 127с² + х² + 24ху + 74у² - хс + 16

This is the final simplified expression.