Question

1) 1-9x²=02) 16+3x²=8x3) 18-x²+3x=0

Answer 1

Ответ:

1)х=1/3

Объяснение:

1)-9х²=-1

х²= -1/-9

х=1/3

2)нет решений

Answer 2

To solve each of these quadratic equations, we need to find the values of "x" that satisfy the equation. We can use different methods to solve quadratic equations, such as factoring, completing the square, or using the quadratic formula. Let's solve each equation step by step:

1. 1 - 9x² = 0

Step 1: Move all terms to one side to set the equation to zero. 9x² - 1 = 0

Step 2: Factor the equation, if possible. In this case, it is a difference of squares. (3x + 1)(3x - 1) = 0

Step 3: Set each factor to zero and solve for "x." 3x + 1 = 0 --> 3x = -1 --> x = -1/3 3x - 1 = 0 --> 3x = 1 --> x = 1/3

So, the solutions for this equation are x = -1/3 and x = 1/3.

2. 16 + 3x² = 8x

Step 1: Move all terms to one side to set the equation to zero. 3x² - 8x + 16 = 0

Step 2: We can use the quadratic formula to find the solutions. The quadratic formula is given by: x = (-b ± √(b² - 4ac)) / 2a

where a = 3, b = -8, and c = 16.

x = [8 ± √((-8)² - 4 * 3 * 16)] / 2 * 3 x = [8 ± √(64 - 192)] / 6 x = [8 ± √(-128)] / 6

Since the discriminant (√(b² - 4ac)) is negative, this equation has no real solutions. The solutions involve imaginary numbers.

3. 18 - x² + 3x = 0

Step 1: Move all terms to one side to set the equation to zero. x² - 3x - 18 = 0

Step 2: Factor the equation, if possible. (x - 6)(x + 3) = 0

Step 3: Set each factor to zero and solve for "x." x - 6 = 0 --> x = 6 x + 3 = 0 --> x = -3

So, the solutions for this equation are x = 6 and x = -3.

To summarize:

1. x = -1/3 or x = 1/3
2. This equation has no real solutions (only imaginary solutions).
3. x = 6 or x = -3