Question

Sin(π-a)-sin(-a)+2cos(3π/2-a)

Answer 1

Ответ:

Объяснение:

=sina+sina-2sina=2sina-2sina=0

Answer 2

Let's simplify the expression step by step:

1. Recall the trigonometric identities:

   • Sin(-x) = -Sin(x)
   • Cos(-x) = Cos(x)

2. Use these identities to simplify the expression: Sin(π - a) - Sin(-a) + 2Cos(3π/2 - a)

   = Sin(π)Cos(a) - Cos(π)Sin(a) + 2Cos(3π/2)Cos(a) + 2Sin(3π/2)Sin(a)

   Note that:

   • Sin(π) = 0
   • Cos(π) = -1
   • Cos(3π/2) = 0
   • Sin(3π/2) = -1

3. Substitute these values back into the expression: = 0 - (-1)Cos(a) + 0 + (-2)Sin(a)

   = Cos(a) + 2Sin(a)

So, the simplified expression is Cos(a) + 2Sin(a).