Question

(x - 3)(х+4)=х(x + 1)-12​

Answer 1

(x - 3)(х+4)=х(x + 1)-12​

х²+4х-3х-12=х²+х-12

х²+х=х²+х

0=0

х - любое число.

Answer 2

●Раскроем скобки.

х²-3х+4х-12=х²+х-12.

●Перенесём (х²+х-12) в левую часть уравнения, помня о том, что знаки меняются.

х²-3х+4х-12-х²-х+12=0.

●Сведём подобные слагаемые.

• х² и (-х²) = 0

• -3х+4х-х = 0

• -12 + 12 = 0

0 = 0.

Ответ: так как равенство 0=0 - верное, => х Є R (х- любое число)

Answer 3

Let's solve the given equation step by step:

Given equation: (x - 3)(x + 4) = x(x + 1) - 12

Expand the left side of the equation using the distributive property: x^2 + 4x - 3x - 12 = x^2 + x - 12

Combine like terms on both sides of the equation: x^2 + x - 12 = x^2 + x - 12

Subtract x^2 and x from both sides of the equation: 0 = 0

The equation 0 = 0 is an identity, which means that it is true for all values of x. This implies that the original equation you provided is also true for all values of x.

In other words, the given equation (x - 3)(x + 4) = x(x + 1) - 12 is satisfied for any real value of x.