Question

(3а+2в)²+(3а-2в)²-2(3а+2в)(2в-3а)-(12а-1)(3а+4)+5(9а-2)=

Answer 1

Ответ:

Ответ : -6

Объяснение:

фотомаф в помощь

Answer 2

Let's simplify the expression step by step:

Given expression: (3а+2в)² + (3а-2в)² - 2(3а+2в)(2в-3а) - (12а-1)(3а+4) + 5(9а-2)

First, let's expand the squares and the products:

(3а+2в)² = (3а+2в)(3а+2в) = 9а² + 6ав + 6ав + 4в² = 9а² + 12ав + 4в² (3а-2в)² = (3а-2в)(3а-2в) = 9а² - 6ав - 6ав + 4в² = 9а² - 12ав + 4в²

Now let's simplify the products:

2(3а+2в)(2в-3а) = 2(6в² - 9а²) = 12в² - 18а² (12а-1)(3а+4) = 36а² + 48а - 3а - 4 = 36а² + 45а - 4

5(9а-2) = 45а - 10

Now let's substitute these simplified expressions back into the original expression and combine like terms:

(9а² + 12ав + 4в²) + (9а² - 12ав + 4в²) - (12в² - 18а²) - (36а² + 45а - 4) + (45а - 10)

Combine the like terms:

9а² + 12ав + 4в² + 9а² - 12ав + 4в² - 12в² + 18а² - 36а² - 45а + 4 + 45а - 10

Now simplify the terms:

(9а² + 9а² + 18а² - 36а²) + (12ав - 12ав) + (4в² + 4в² - 12в²) + (-45а + 45а) + (4 - 10)

Combine the like terms again:

(36а² - 18а²) + (0) + (-4в²) + (0) + (-6)

Finally, calculate the values:

18а² - 4в² - 6

So, the simplified form of the given expression is: 18а² - 4в² - 6