Question

2x2−11x+5=0. x1= x2=

Answer 1

Ответ:

5/7

Объяснение:

4x-11x+5=0

7x=5

x=5/7

Answer 2

Ответ:

фоточка тебе в помощь ;)

Answer 3

To find the solutions for the quadratic equation $2x^2 - 11x + 5 = 0$, you can use the quadratic formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this equation, $a = 2$, $b = -11$, and $c = 5$.

Calculate the discriminant ($b^2 - 4ac$): $b^2 - 4ac = (-11)^2 - 4 \cdot 2 \cdot 5 = 121 - 40 = 81$

Since the discriminant is positive, the quadratic equation has two distinct real solutions.

Now use the quadratic formula to find the solutions:

$x = \frac{-(-11) \pm \sqrt{81}}{2 \cdot 2} = \frac{11 \pm 9}{4}$

Simplify the expressions: $x_1 = \frac{11 + 9}{4} = \frac{20}{4} = 5$ $x_2 = \frac{11 - 9}{4} = \frac{2}{4} = \frac{1}{2}$

So, the solutions for the equation $2x^2 - 11x + 5 = 0$ are $x_1 = 5$ and $x_2 = \frac{1}{2}$.