Question

1/2arccos√3/2+1/3arccos(-√2/2)​

Answer 1

1/2arccos√3/2+1/3arccos(-√2/2)
1/2*p/6+1/3*3p/4
P/12+4/p
P/3
Ответ: P/3

Answer 2

The expression you've provided seems to be a combination of trigonometric functions involving inverse cosine (arccos) and constants. Let's break it down step by step:

1. 1/2 * arccos(√3/2): The value of arccos(√3/2) is π/6. So, when you multiply it by 1/2, you get (1/2) * (π/6) = π/12.

2. 1/3 * arccos(-√2/2): The value of arccos(-√2/2) is 3π/4. So, when you multiply it by 1/3, you get (1/3) * (3π/4) = π/4.

Now, let's add the results of the two steps:

π/12 + π/4 = (π + 3π) / 12 = 4π / 12 = π / 3.

So, the simplified value of the expression is π / 3.