Question

(x²+2x)/3 = (4x+1)/5 ​

Answer 1

(x²+2x)/3 = (4x+1)/5

5x²+10x=12x+3

5x²-2x-3=0

D=(-2)²-4*5*(-3)=4+60=64

√D=8

x=(2+8)/10=1

x=(2-8)/10= -0,6

Answer 2

Ответ:

x1=-3/5 x2=1

Объяснение:

ну это и есть ответ

Answer 3

To solve the equation $\frac{x^2 + 2x}{3} = \frac{4x + 1}{5}$ for $x$, you can follow these steps:

Step 1: Clear the fractions by multiplying both sides of the equation by the least common multiple (LCM) of the denominators, which is $3 \times 5 = 15$:

$$15 \cdot \frac{x^2 + 2x}{3} = 15 \cdot \frac{4x + 1}{5}$$

Simplify both sides:

$$5(x^2 + 2x) = 3(4x + 1)$$

Step 2: Distribute the constants and variables on both sides:

$$5x^2 + 10x = 12x + 3$$

Step 3: Move all terms to one side of the equation to set it equal to zero:

$$5x^2 + 10x - 12x - 3 = 0$$

Simplify:

$$5x^2 - 2x - 3 = 0$$

Step 4: This is a quadratic equation. You can solve it using the quadratic formula:

The quadratic formula is given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, $a = 5$, $b = -2$, and $c = -3$.

Calculate the discriminant, $b^2 - 4ac$:

$b^2 - 4ac = (-2)^2 - 4 \cdot 5 \cdot (-3) = 4 + 60 = 64$

Since the discriminant is positive, the quadratic equation has two real roots.

Now, plug the values into the quadratic formula:

$x = \frac{-(-2) \pm \sqrt{64}}{2 \cdot 5} = \frac{2 \pm 8}{10}$

Simplify:

$x_1 = \frac{10}{10} = 1$

$x_2 = \frac{-6}{10} = -\frac{3}{5}$

So, the solutions for the equation are $x = 1$ and $x = -\frac{3}{5}$.