Question

2). {█(3х/4+ 3у/8= 9/[email protected]х/3= у/12+ 2/3)┤

Answer 1

Ответ:

шо

Объяснение:

это я не понял

Answer 2

It seems like you've provided a system of equations, but the formatting is a bit unclear. I'll do my best to interpret and solve the system of equations:

The system of equations you've given is:

1. $\frac{3x}{4} + \frac{3y}{8} = \frac{9}{\sqrt{x}}$
2. $\frac{x}{3} = \frac{y}{12} + \frac{2}{3}$

Let's solve this system step by step.

Starting with the second equation, we can rewrite it to isolate $x$: $\frac{x}{3} = \frac{y}{12} + \frac{2}{3}$

Multiply both sides by 3 to eliminate the fraction: $x = 4y + 2$

Now we can substitute this value of $x$ into the first equation: $\frac{3x}{4} + \frac{3y}{8} = \frac{9}{\sqrt{x}}$

Substitute $x = 4y + 2$: $\frac{3(4y + 2)}{4} + \frac{3y}{8} = \frac{9}{\sqrt{4y + 2}}$

Simplify the fractions: $3y + \frac{3}{2} + \frac{3y}{8} = \frac{9}{\sqrt{4y + 2}}$

Combine like terms: $\frac{24y + 9}{8} + \frac{3}{2} = \frac{9}{\sqrt{4y + 2}}$

Now, we can work with the square root equation: $\frac{24y + 9 + 12}{8} = \frac{9}{\sqrt{4y + 2}}$

Simplify: $\frac{24y + 21}{8} = \frac{9}{\sqrt{4y + 2}}$

Cross-multiply: $72y + 63 = 72y + 36$

Subtract $72y$ from both sides: $63 = 36$

This equation is inconsistent, which means there is no solution that satisfies both original equations. It's possible that there might have been an error in the given equations or some misunderstanding in the formatting.

If you need further assistance or if there's anything else I can help you with, please let me know!