Question

1 . (2х – 3)(2х + 3) = 4х(х + 1) – 1

Answer 1

Ответ:

-2

Объяснение:

(2х – 3)(2х + 3) = 4х(х + 1) – 1

$4x^{2} +6x-6x-9=4x^{2} +4x-1\\4x^{2} +6x-6x-9-4x^{2} -4x+1=0\\-4x-8=0\\-4x=8\\x=-2$

Answer 2

Let's simplify the expression on the left side of the equation:

(2x - 3)(2x + 3)

Using the FOIL method (First, Outer, Inner, Last), we can multiply the terms:

First: 2x * 2x = 4x^2 Outer: 2x * 3 = 6x Inner: -3 * 2x = -6x Last: -3 * 3 = -9

Combining the terms, we have:

4x^2 + 6x - 6x - 9

Simplifying further, the middle terms cancel each other out:

4x^2 - 9

Now let's compare this with the expression on the right side of the equation:

4x(x + 1) - 1

Using the distributive property, we multiply 4x by each term inside the parentheses:

4x * x = 4x^2 4x * 1 = 4x

Combining the terms, we have:

4x^2 + 4x - 1

Comparing this expression with the simplified expression on the left side, we see that they are not equal. Therefore, the original equation

(2x - 3)(2x + 3) = 4x(x + 1) - 1

is not true.