Question

(х – 3)(х + 1) + (х + 5)(х – 5)= 4 – 2х

Answer 1

Ответ:

х=1/3

Объяснение:

(х-3)(х+1)+(х+5)(х-5)=4-2х

2х-х+3х-х=4+2-5

3х=1

х=1/3

Answer 2

Ответ:

Х1=-4; х2=4

Объяснение:

Х^2+х-3х-3+х^2-25=4-2х

2х^2-2х-28=4-2х

2х^2-28=4

2х^2=4+28

2х^2=32

х^2=16

х1=4

х2=-4

Answer 3

To solve the given equation, we can start by simplifying both sides of the equation and then solving for the variable $x$:

Given equation: $(x - 3)(x + 1) + (x + 5)(x - 5) = 4 - 2x$

Let's start by simplifying each of the products on the left-hand side:

$(x - 3)(x + 1) = x^2 - 3x + x - 3 = x^2 - 2x - 3$ $(x + 5)(x - 5) = x^2 - 5x + 5x - 25 = x^2 - 25$

Now substitute these simplified expressions back into the equation:

$x^2 - 2x - 3 + x^2 - 25 = 4 - 2x$

Combine like terms on the left-hand side:

$2x^2 - 28 = 4 - 2x$

Move all terms to one side to set the equation to zero:

$2x^2 + 2x - 32 = 0$

Now we have a quadratic equation. To solve for $x$, we can factor the equation if possible, or use the quadratic formula:

The quadratic formula is given by: $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

In this case, the coefficients are $a = 2$, $b = 2$, and $c = -32$. Substituting these values into the quadratic formula:

$x = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 2 \cdot (-32)}}{2 \cdot 2}$ $x = \frac{-2 \pm \sqrt{4 + 256}}{4}$ $x = \frac{-2 \pm \sqrt{260}}{4}$ $x = \frac{-2 \pm 2\sqrt{65}}{4}$ $x = \frac{-1 \pm \sqrt{65}}{2}$

So, the solutions for $x$ are: $x = \frac{-1 + \sqrt{65}}{2}$ $x = \frac{-1 - \sqrt{65}}{2}$

These are the solutions to the given equation.