Question

(2√320-7√20-√45)*2√45

Answer 1

Ответ:

(2√320-7√20-√45)*2√45

$(2\sqrt{64*5} -7\sqrt{4*5} -\sqrt{9*5} )*2\sqrt{9*5} = (2*8\sqrt{5} -7*2\sqrt{5} -3\sqrt{5} )*2*3\sqrt{5} = -\sqrt{5} *6\sqrt{5} =-6*5=-30$

Объяснение:

Answer 2

To simplify the expression $(2\sqrt{320} - 7\sqrt{20} - \sqrt{45}) \times 2\sqrt{45}$, we can follow these steps:

1. Simplify the square roots:

   • $\sqrt{320} = \sqrt{16 \cdot 20} = 4\sqrt{20}$
   • $\sqrt{20} = 2\sqrt{5}$
   • $\sqrt{45} = 3\sqrt{5}$

2. Substitute the simplified square roots back into the expression: $(2 \cdot 4\sqrt{20} - 7 \cdot 2\sqrt{5} - 3\sqrt{5}) \times 2\cdot 3\sqrt{5}$

3. Distribute the constants: $(8\sqrt{20} - 14\sqrt{5} - 3\sqrt{5}) \times 6\sqrt{5}$

4. Combine like terms: $(8\sqrt{20} - 17\sqrt{5}) \times 6\sqrt{5}$

5. Distribute the constants again: $48\sqrt{20} - 102\sqrt{5}$

6. Simplify the square root of 20: $48\sqrt{20} = 48 \cdot 2\sqrt{5} = 96\sqrt{5}$

7. Combine like terms: $96\sqrt{5} - 102\sqrt{5} = -6\sqrt{5}$

So, the simplified result is $-6\sqrt{5}$.